Schumacher Electric PID-410 Manual Del Usuario página 8

PROBLEM
Alarm is on.
(continued)
Inverter does
not turn on.
REASON
Display shows voltage in
between 10.5 and 11.0V.
Display shows . 12V
voltage is too high.
Display shows .
Device demands more
than the inverter's
continuous power rating.
Display shows .
Inverter is too hot.
Poor contact at terminals.
Fuse is blown.
Inverter may be
defective.
12V battery is low.
Recharge/replace battery.
The inverter will automatically shut off
after battery voltage reaches 10.5V.
If in a vehicle, repair/replace the
alternator or charging system.
Use a properly sized and rated 12V
battery.
If the input voltage returns to 15V or
less, the inverter will automatically
restart.
Cycle the inverter power OFF and ON.
If problem persists, use a larger
inverter or a smaller device.
Increase the ventilation to the inverter.
Move the inverter to a cooler area.
Reduce the power consumption
of the device. The inverter will
automatically reset after cooling.
Check for poor connection to
battery or power supply. Make sure
connection points are clean. Rock
clamps back and forth for a better
connection.
A blown fuse is usually caused by
reverse polarity or a short circuit
within the inverter.
To replace, contact a qualified service
technician who will diagnose the
inverter and replace the fuse(s) with
the appropriate replacement(s).
See warranty and call Customer
Service.
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SOLUTION