Ferroli OMNIA ST 3.2 Manual De Instalación, Uso Y Mantenimiento página 72

Start
Input from installer:
- Total refrigerant charge (m
- Area of room A (A ) (m
roomA
Use table 2 to calculate the
maximum refrigerant charge (m
allowed for room A.
m ≥mc?
max
yes
The unit can be installed in room A, and
without further room size or ventilation
requirements.
Unit can be installed at room A if:
- 2 ventilation openings (permanently open) are provided between room A and B, 1 at the top and 1 at the bottom.
- Bottom opening:The bottom opening must meet the minimum area requirements(VA
opening starts from the floor, the height must be ≥20mm. The bottom of the opening must be situated≤100mm from the floor. At least 50% of the required
opening area must be situated <200 mm from the floor. The entire area of the opening must be situated <300 mm from the floor.
- Top opening:The area of the top opening must be larger than or equal to the bottom opening. The bottom of the top opening must be situated at least 1.5
m above the top of the bottom opening.
- Ventilation openings to the outside are NOT considered suitable ventilation openings (the user can block them when it is cold).
The flow chart uses the following tables:
Table. 2 - Maximum refrigerant charge allowed in a room
A [m ] 29 30 31
2
mmax [kg] 1,85 1,88 1,91 1,94 1,97 2,00 2,03 2,06 2,09 2,11 2,14 2,17 2,19 2,22 2,25 2,27 2,30 2,32 2,35 2,37 2,40 2,42 2,45 2,47 2,50
NOTE
For floor standing models, the value of "Installation height (H)" is considered 600 mm to comply to IEC 60335-2-40:2018 Clause GG2. For intermediate
Aroom values(i.e. when A is between two values from the table), consider the value that corresponds to the lower A
room
m , consider the value that corresponds to "A
2
Table. 3 - Minimum floor area
mc [kg] 1,9 2
A [m ] 30,7 34,0
2
mintotal
72
EN
Input from installer:
- Area of adjacent room B (A
Use table 3 to calculate the
total minimum floor area (A
)(kg)
red for the total refrigerant charge (m
c
)
2
)(kg)
max
Determine the refrigerant amount that
exceeds m
no
Use table 4 and dm to calculate the
minimum opening area for natural
ventilation between room A and room
B(VA
min
32 33 34 35 36 37 38
=3,5 m ".
2
room
2,1 2,2 2,3 2,4
37,5 41,2 45,0 49,0
Cod. 3541V991 - Rev. 00 - 09/2021
) (m )
2
roomB
)(m )requi-
2
mintotal
)
c
A ≤A +A ?
min total roomA roomB
yes
(dm)(kg).(dm=m -m )
max c max
)(cm 2 )
).It must be as close as possible to the floor.If the ventilation
min
39 40 41 42 43 44
2,5
53,2
OMNIA ST 3.2
no
Contact your dealer
45 46 47 48 49 50
value from the table. If A
room
51 52 53
=3,6
room