Relay Outputs; Analog Output; Controller Settings - Grundfos TPE 1000 Serie Instrucciones De Instalación Y Funcionamiento

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11.9 Relay outputs

Function (terminal)
Relay output 1 (NC, C1, NO)
Relay output 2 (NC, C2, NO)
The pump incorporates two signal relays for potential-free
signalling. See section 18. Signal relays for further information.
The signal relays can be configured to be activated by one of the
following incidents:
Ready
Operation
Alarm
Warning
Limit 1 exceeded
Limit 2 exceeded
Pump running
Control of external fan
Not active.

11.10 Analog output

Whether the analog output is available or not, depends on the
functional module fitted in the pump:
Function (terminal)
Analog output
To set up the analog output, make the settings below.
Output signal
0-10 V
0-20 mA
4-20 mA.
Function of analog output
Actual speed
Actual value
Resulting setpoint
Motor load
Motor current
Limit 1 exceeded
Limit 2 exceeded
Flow rate.
22

11.11 Controller settings

The pumps have a factory default setting of gain (K
FM 300
time (T
).
i
(advanced)
However, if the factory setting is not the optimum setting, the gain
and the integral time can be changed:
Set the gain (K
Set the integral-action time (T
3600 s.
If 3600 s is selected, the controller will function as a P
controller.
Furthermore, the controller can be set to inverse control.
This means that if the setpoint is increased, the speed will be
reduced. In the case of inverse control, the gain (K
within the range from -0.1 to -20.
Guidelines for setting of PI controller
The tables below show the recommended controller settings:
Differential-pressure
FM 300
(advanced)
L1 = Distance ft (m) between pump and sensor.
Temperature control
1)
In heating systems, an increase in pump performance will
result in a rise in temperature at the sensor.
2)
In cooling systems, an increase in pump performance will
result in a drop in temperature at the sensor.
L2 = Distance ft (m) between heat exchanger and sensor.
) within the range from 0.1 to 20.
p
) within the range from 0.1 to
i
K
p
control
p
0.5
p
p
p
L1
0.5
L1
K
p
Heating
1)
system
0.5
t
L2
L2
t
0.5
) and integral
p
) must be set
p
T
i
0.5
L1 < 16.4 ft (5 m): 0.5
L1 > 16.4 ft (5 m): 3
L1 > 32.8 ft (10 m): 5
T
i
Cooling
2)
system
-0.5
10 + 5L2
-0.5
30 + 5L2

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